GBRC JRF Recruitment: Complete Screening Test Syllabus, 20-Question Mock Test & Interview Guide
Advertisement No: GBRC/Recruitment/2026/02 | Gujarat Biotechnology Research Centre
📌 Important Examination Notification Summary
- Post Name: Junior Research Fellow (JRF)
- Advt No.: GBRC/Recruitment/2026/02
- Exam Date: August 5, 2026
- Reporting Time: 08:30 AM
- Venue: GBRC, 6th Floor, MS Building, Sector 11, Gandhinagar - 382011
- Exam Format: Multiple-Choice Questions (MCQs) followed by Technical Interview
- Mandatory Items: Valid Photo ID (Aadhaar, Passport, etc.) and Examination Call Letter
📚 Detailed Subject & Topic Wise Syllabus Breakdown
To successfully crack the GBRC JRF screening test, candidates must focus their preparation on three core modules specified in the official syllabus layout:
1. Project Work & Practical Lab Techniques
- Master's Thesis / Project Methodology
- Buffer preparations & Dilution math (C1V1 = C2V2)
- Spectrophotometry & Fluorometry (A260 / A280 purity)
- Gel Electrophoresis (PAGE & Agarose)
- PCR, qPCR, and Primer Design
- Recombinant DNA Techniques & Cloning Vectors
2. Core Biological Sciences
- Molecular Biology: Replication, Transcription, Translation
- Biochemistry: Enzyme Kinetics (Km, Vmax), Metabolism
- Genetics: Mendelian Rules, Mutations, Gene Mapping
- Cell Biology: Cell Signaling, Apoptosis, Organelles
- Immunology: Antibodies, ELISA, Flow Cytometry
3. Related Fields & Applied Science
- Bioinformatics: BLAST, Sequence Alignments, Databases
- Biostatistics: t-test, ANOVA, Standard Deviation
- Advanced Tools: Next-Gen Sequencing (NGS), CRISPR-Cas9
- Microbiology: Cell Wall Chemistry, Culture Techniques
📝 Interactive Original 20-Question Mock Test
Practice with this full-length original mock test designed to match the difficulty level of GBRC previous screening exams. Click on "Show Answer & Explanation" under each question to verify your answers.
- A) Within the 1.5 kb BamHI fragment
- B) Exactly 1.0 kb away from one of the BamHI sites in the larger 3.5 kb region
- C) Overlapping with one of the BamHI recognition sequences
- D) It is impossible to obtain these fragments
Show Answer & Explanation
Explanation: The two BamHI sites divide the 5.0 kb plasmid into 1.5 kb and 3.5 kb fragments. The single EcoRI site cuts within the larger 3.5 kb fragment, cleaving it into 2.5 kb and 1.0 kb pieces.
- A) High efficiency of Taq polymerase
- B) Formation of non-specific amplification products or primer-dimers
- C) Denaturation of target DNA at two distinct melting temperatures
- D) Contamination of EDTA in the reaction mix
Show Answer & Explanation
Explanation: SYBR Green binds to all double-stranded DNA. Two distinct melting peaks denote two different DNA products (e.g., your target amplicon and non-specific primer-dimers).
- A) Integrase (Int) and Excisionase (Xis) only
- B) BP Clonase enzyme mix
- C) LR Clonase mix containing Integrase (Int), Integration Host Factor (IHF), and Excisionase (Xis)
- D) T4 DNA Ligase and Alkaline Phosphatase
Show Answer & Explanation
Explanation: The LR recombination reaction between attL and attR sites is catalyzed specifically by the LR Clonase enzyme mix (Int, IHF, and Xis).
- A) 28%
- B) 22%
- C) 44%
- D) 56%
Show Answer & Explanation
Explanation: %C = %G = 28%. Total G+C = 56%. Remaining A+T = 100% - 56% = 44%. Since %A = %T, Adenine = 44% / 2 = 22%.
- A) Ampicillin gene is inactivated
- B) Insertional inactivation disrupts α-complementation of β-galactosidase, preventing X-Gal cleavage
- C) X-Gal is utilized as a carbon source
- D) IPTG competitively inhibits β-galactosidase
Show Answer & Explanation
Explanation: Inserting foreign DNA into the lacZα gene prevents functional β-galactosidase synthesis, leaving colonies white as X-Gal is not cleaved.
- A) 0.25 Vmax
- B) 0.50 Vmax
- C) 0.75 Vmax
- D) 0.80 Vmax
Show Answer & Explanation
Explanation: Using v = (Vmax × [S]) / (Km + [S]) = (Vmax × 7.5) / (2.5 + 7.5) = (7.5 / 10) Vmax = 0.75 Vmax.
- A) Cleaves disulfide bonds
- B) Imparts a uniform negative charge-to-mass ratio to proteins while disrupting non-covalent bonds
- C) Acts as a pH buffer
- D) Binds to basic amino acids
Show Answer & Explanatio
Explanation: SDS denatures proteins and confers a uniform negative charge density so migration speed depends strictly on molecular weight.
- A) 12.5 mL
- B) 25.0 mL
- C) 5.0 mL
- D) 1.25 mL
Show Answer & Explanation
Explanation: C1V1 = C2V2 ⇒ (1000 mM) × V1 = (50 mM) × (250 mL) ⇒ V1 = 12.5 mL.
- A) It gains a net positive charge
- B) It undergoes structural denaturation
- C) Its net charge becomes zero, halting movement in the electric field
- D) It binds irreversibly to gel ampholytes
Show Answer & Explanation
Explanation: At pI (isoelectric point), a protein's net charge is zero, stopping its migration in an electric field.
- A) Size-Exclusion Chromatography
- B) Ion-Exchange Chromatography
- C) Hydrophobic Interaction Chromatography
- D) Affinity Chromatography
Show Answer & Explanation
Explanation: Affinity chromatography utilizes high-specificity biological interactions (e.g., Ni-NTA and His-tag, antibody-antigen).
- A) Act as fluorescent markers
- B) Hybridize to complementary oligos on the flow cell for bridge amplification
- C) Cleave single-stranded DNA
- D) Amplify bacterial contaminants
Show Answer & Explanation
Explanation: Adapters bind to lawn oligos on the flow cell surface, allowing cluster generation via bridge PCR amplification.
- A) BLASTn
- B) BLASTp
- C) BLASTx
- D) tBLASTn
Show Answer & Explanation
Explanation: BLASTx translates a nucleotide query in all 6 reading frames and compares it against a protein database.
- A) Paired t-test
- B) Student's t-test
- C) One-way ANOVA
- D) Chi-Square Test
Show Answer & Explanation
Explanation: One-way ANOVA is used to determine statistically significant differences between the means of three or more independent groups.
- A) 20% chance of incorrect alignment
- B) Very high statistical significance with minimal chance of random match
- C) 20% sequence identity
- D) Low alignment score
Show Answer & Explanation
Explanation: An E-value near zero indicates an extremely low probability that the match occurred purely by random chance.
- A) TATA box
- B) Protospacer Adjacent Motif (PAM)
- C) Shine-Dalgarno sequence
- D) Polyadenylation signal
Show Answer & Explanation
Explanation: Cas9 requires a PAM motif (e.g., 5'-NGG-3') downstream of the target site to recognize and cleave target DNA.
- A) 25 µg/mL
- B) 40 µg/mL
- C) 50 µg/mL
- D) 80 µg/mL
Show Answer & Explanation
Explanation: Concentration = 0.80 × 50 µg/mL = 40 µg/mL.
- A) Teichoic acid
- B) Peptidoglycan
- C) Lipopolysaccharide (LPS / Lipid A)
- D) Mycolic acid
Show Answer & Explanation
Explanation: The Lipid A component of Lipopolysaccharide (LPS) acts as a strong endotoxin in Gram-negative bacteria.
- A) PEP carboxylase
- B) RuBisCO
- C) Malate dehydrogenase
- D) Transketolase
Show Answer & Explanation
Explanation: RuBisCO catalyzes the fixation of CO₂ into 3-phosphoglycerate during dark reactions.
- A) IgM
- B) IgA
- C) IgG
- D) IgE
Show Answer & Explanation
Explanation: IgG is the only antibody class capable of crossing the placenta via specialized Fc receptors.
- A) To neutralize culture toxins
- B) To cleave cell-adhesion proteins and chelate divalent cations for cell detachment
- C) To induce G2/M cell cycle arrest
- D) To supply essential nutrients
Show Answer & Explanation
Explanation: Trypsin breaks cell-surface proteins while EDTA chelates Ca²⁺/Mg²⁺ ions necessary for cell adhesion.
🎙️ How to Clear the GBRC JRF Technical Interview
Shortlisted candidates post-screening will face an expert interview panel. Focus on these top interview preparation areas:
1. Explain Your Dissertation Project Confidently
Expect at least 50% of questions from your Master's research work. Be ready to explain your hypothesis, methodology, control setup, experimental limitations, and practical applications.
2. Practical Lab Troubleshooting Scenarios
Panels frequently evaluate real-time problem solving. Be ready to explain how you handle PCR non-specific bands, RNA degradation, low DNA yield, or Western Blot background noise.
3. Alignment with GBRC Thrust Areas
Familiarize yourself with GBRC’s focus domains: Marine Biotechnology, Agricultural Genomics, Environmental Diagnostics, and Human Pathogen Sequencing (BSL-2/BSL-3 operations).
❓ Frequently Asked Questions (FAQ)
Q1: What is the exam venue and time for GBRC JRF 2026?
The exam takes place at GBRC, 6th Floor MS Building, Sector 11, Gandhinagar-382011 on August 5, 2026. Reporting time is 8:30 AM.
Q2: What topics are covered in the GBRC JRF screening test?
The test covers practical project work/lab techniques, core life sciences (Molecular Biology, Genetics, Biochemistry), and related domains (Bioinformatics, Biostatistics).
Q3: What documents are mandatory on exam day?
Bring an official photo identity card (Aadhaar, Voter ID, Passport) along with a printed copy of your exam invitation call letter/email.
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