GBRC JRF Screening Test & Interview Guide (Part 2): 20 New MCQs, Advanced Interview Qs & Reference Books
Exclusive Focus on Previous GBRC Exam Trends & Research Aptitude
📖 Best Reference Books for GBRC JRF Preparation
To build a rock-solid foundation for both the screening test and technical interview, subject experts recommend referencing these standard textbooks:
Molecular Biology & Genetics
- Molecular Biology of the Gene – Watson et al.
- Genetics: Analysis and Principles – Robert J. Brooker
- Key Focus: Replication machinery, operons, gene regulation, DNA repair mechanisms.
Biochemistry & Enzymology
- Lehninger Principles of Biochemistry – Nelson & Cox
- Key Focus: Enzyme kinetics (Lineweaver-Burk plots), metabolic pathways, protein folding & purification.
Recombinant DNA & Lab Techniques
- Principles of Gene Manipulation and Genomics – Primrose & Twyman
- Wilson and Walker’s Principles and Techniques of Biochemistry and Molecular Biology
- Key Focus: Cloning vectors, NGS platforms, Spectroscopy math, Electrophoresis troubleshooting.
Bioinformatics & Biostatistics
- Bioinformatics: Sequence and Genome Analysis – David W. Mount
- Biostatistical Analysis – Jerrold H. Zar
- Key Focus: BLAST algorithms, sequence alignment, ANOVA, hypothesis testing.
📝 Practice Set (Part 2): 20 New High-Yield MCQs
These original questions reflect actual GBRC screening exam trends, featuring numerical lab math, advanced molecular biology, and biotechnology tools.
- A) 10 mL Stock + 490 mL Water
- B) 50 mL Stock + 450 mL Water
- C) 25 mL Stock + 475 mL Water
- D) 5 mL Stock + 495 mL Water
Show Answer & Explanation
Explanation: Using C1V1 = C2V2 ⇒ (50X) × V1 = (1X) × (500 mL) ⇒ V1 = 10 mL stock. Water required = 500 - 10 = 490 mL.
- A) Absence of a 2'-OH group on the ribose ring
- B) Absence of a 3'-OH group on the deoxyribose ring
- C) Presence of a phosphate group at the 3' position
- D) Methylation at the 5' position
Show Answer & Explanation
Explanation: ddNTPs lack a 3'-OH group needed for phosphodiester bond formation with the next incoming dNTP, terminating elongation.
- A) Decreasing Vmax while keeping Km unchanged
- B) Increasing Km while leaving Vmax unchanged
- C) Decreasing both Km and Vmax proportionally
- D) Increasing both Km and Vmax
Show Answer & Explanation
Explanation: Competitive inhibitors bind to the active site, increasing the apparent Km (reducing affinity). High substrate concentration outcompetes the inhibitor, leaving Vmax unchanged.
- A) To ligate mutated PCR fragments
- B) To selectively digest methylated non-mutated parental plasmid DNA
- C) To phosphorylate 5' ends of synthetic primers
- D) To linearize the mutated vector prior to transformation
Show Answer & Explanation
Explanation: DpnI specifically digests methylated/hemimethylated DNA (parental plasmid isolated from E. coli), enriching the non-methylated mutated PCR product.
- A) Western Blotting
- B) RNA-Seq (Transcriptomics)
- C) Chromatin Immunoprecipitation (ChIP-Seq)
- D) Southern Blotting
Show Answer & Explanation
Explanation: RNA-Seq provides comprehensive quantitative profiling of the entire transcriptome across different conditions.
- A) Low agarose concentration
- B) Running the gel at excessively high voltage, causing uneven heating across the gel
- C) Over-digestion with restriction enzymes
- D) Using freshly prepared TAE buffer
Show Answer & Explanation
Explanation: High voltage generates excessive heat, causing the center of the gel to run faster than the cooler outer edges, resulting in curved/smiling bands.
- A) Peptidoglycan
- B) Lipopolysaccharide (LPS)
- C) Flagellin
- D) Single-stranded RNA
Show Answer & Explanation
Explanation: TLR4 specifically recognizes Gram-negative lipopolysaccharides (LPS) to trigger innate immune cascades.
- A) Pure double-stranded DNA
- B) RNA contamination
- C) Protein or phenol contamination
- D) High salt concentration
Show Answer & Explanation
Explanation: Pure DNA has an A260/A280 ratio of ~1.8. A significantly lower ratio (<1.6) indicates protein or phenol contamination absorbing at 280 nm.
- A) Restriction enzyme cleavage
- B) Vector self-ligation (re-circularization)
- C) Insert DNA degradation
- D) Transformation into competent cells
Show Answer & Explanation
Explanation: Alkaline phosphatase removes 5'-phosphate groups from linearized vector ends, preventing DNA ligase from self-ligating the vector back together.
- A) Mann-Whitney U test
- B) Pearson correlation
- C) Chi-Square (χ²) test
- D) Two-way ANOVA
Show Answer & Explanation
Explanation: The Chi-Square test compares observed versus expected frequencies for categorical data.
- A) Elongation of the RNA chain
- B) Specific promoter recognition and transcription initiation
- C) Rho-dependent termination
- D) Polyadenylation of mRNA
Show Answer & Explanation
Explanation: The sigma factor directs core RNA polymerase to bind specifically to promoter sequences (-10 and -35 regions).
- A) Uses less DNA polymerase
- B) Absolute quantification without requiring a standard reference curve
- C) Faster run time
- D) Does not require fluorescence detection
Show Answer & Explanation
Explanation: dPCR partitions samples into thousands of micro-reactions to achieve absolute nucleic acid copy number measurement without standard curves.
- A) Precise point mutation insertion
- B) Random insertions/deletions (indels) causing gene knockout
- C) Large chromosome duplication
- D) Homologous recombination
Show Answer & Explanation
Explanation: NHEJ is an error-prone double-strand break repair pathway that introduces frameshift indels, knocking out target gene function.
- A) Alanine
- B) Serine
- C) Leucine
- D) Valine
Show Answer & Explanation
Explanation: Protein kinases phosphorylate hydroxyl group-containing amino acids: Serine, Threonine, and Tyrosine.
- A) Omega (ω) peptide
- B) Alpha (α) peptide
- C) Sigma (σ) peptide
- D) Zinc-finger domain
Show Answer & Explanation
Explanation: Plasmid vectors encode the LacZα fragment which complements host mutant LacZΩ to restore enzymatic activity (α-complementation).
- A) To stain proteins blue
- B) To reduce disulfide bonds between cysteine residues
- C) To increase sample density
- D) To maintain buffer pH
Show Answer & Explanation
Explanation: Reducing agents like BME or DTT cleave covalent disulfide bonds (-S-S-), fully unfolding protein subunits.
- A) Max Score
- B) E-value (Expect value)
- C) Identity percentage
- D) Query Cover
Show Answer & Explanation
Explanation: The E-value describes the background noise level; lower E-values indicate higher statistical significance.
- A) Cell surface antigenic marker density
- B) Internal cellular complexity / granularity
- C) Relative cell size
- D) Total DNA content
Show Answer & Explanation
Explanation: Forward Scatter (FSC) correlates with cell size, whereas Side Scatter (SSC) indicates internal granularity/complexity.
- A) Plasmid
- B) Cosmid
- C) Bacterial Artificial Chromosome (BAC)
- D) Bacteriophage Lambda
Show Answer & Explanation
Explanation: BACs can carry large genomic fragments ranging from 100 to 350 kb, ideal for constructing genomic libraries.
- A) Solubilizes membrane lipids
- B) Chelates divalent cations (Mg²⁺, Ca²⁺) to inhibit cellular nucleases
- C) Precipitates genomic DNA
- D) Denatures proteins
Show Answer & Explanation
Explanation: DNases and RNases require divalent cations like Mg²⁺ for enzymatic activity. EDTA sequesters these ions, preserving nucleic acid integrity.
🎙️ Actual GBRC JRF Interview Questions & Answering Tips
Based on feedback from previously interviewed candidates, the GBRC technical board evaluates research clarity, lab safety awareness, and practical troubleshooting ability. Review these top 10 scenario-based questions:
Key Answer Approach: Mention running a gradient PCR around calculated Tm (typically Tm - 5°C), increasing annealing temperature step-wise, adding DMSO/betaine co-solvents, or using Touchdown PCR.
Key Answer Approach: Low 260/230 indicates residual guanidine thiocyanate, salts, or carbohydrates. Explain re-precipitating RNA with sodium acetate and 70% ethanol washes or column purification.
Key Answer Approach: Demonstrate knowledge of Biosafety Level 2/3 operations, Class II Type A2 Laminar Air Flow cabinets, personal protective equipment (PPE), PPE disposal, and autoclaving procedures.
Key Answer Approach: Explain the pH difference (pH 6.8 vs. pH 8.8) and how glycine zwitterions form moving boundary fronts (leading Cl⁻ and trailing glycine) to concentrate protein samples into sharp bands prior to separation.
Key Answer Approach: Verify vector-to-insert molar ratios (e.g., 1:3 or 1:5), check T4 DNA ligase and ATP activity, quantify digested ends, ensure thorough removal of restriction enzyme carrying over, and test transformation competency.
Key Answer Approach: Highlight high accuracy (>99.9%) in Illumina versus long reads in Nanopore that span repetitive genomic regions, emphasizing hybrid assembly approaches combining both.
Key Answer Approach: Star activity is non-specific cleavage occurring under non-optimal conditions (excess glycerol >5%, incorrect buffer ionic strength, high enzyme concentration, or prolonged incubation). Prevent it by using High-Fidelity (HF) enzymes and recommended reaction volumes.
Key Answer Approach: State that reference genes must be validated under specific treatment conditions using software like geNorm or NormFinder to ensure stable expression levels across all sample groups.
Key Answer Approach: Mention reversible staining of the PVDF/NC membrane with Ponceau S stain to confirm uniform protein transfer from gel to membrane before blocking.
Key Answer Approach: Align your personal Master's research experience with GBRC projects (e.g., metagenomics, agricultural biotechnology, or clinical genomics) to show genuine enthusiasm and readiness.
Combine Part 1 and Part 2 to complete your preparation for GBRC JRF Screening & Interview!

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